Theory > Physics > 2001 > PART I > 2
WASSCE
A lead shot is projected from the ground level with a velocity u at an angle θ to horizontal. Given The time , t for the lead shot to reach its maximum height as t = usinθ/g. where ''g'' is the acceleration of free fall due to gravity, show that the greatest height reached by body is hmax = u2sin2θ/2g
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