In the calibration of an ammeter using Faraday's law of electrolysis, the ammeter reading is kept constant at 1.20A. If 0.990g of copper is deposited in 40 minutes, the correction to be applied to the ammeter is
[e.c.e. of copper = 3.3 x 10-4gC-1]
A.
0.30A
B.
0.04A
C.
0.05A
D.
0.06A
Answer: C
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