In recharging a lead-acid accumulator,the reaction at the cathode can be represented as
A.
Pb2+(aq) + SO42-(aq)→PbSO4(s)
B.
Pb2+(aq) + 2e- → Pb(s)
C.
Pb2+(aq) + H2O(l) → PbO2(s) + 4H+ + 4e-
D.
Pb(s) → Pb2+(aq) + 2e-
Answer: D
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